2x^ {2}4xy=0 2 x 2 − 4 x − y = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 2 for a, 4 for b, and y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} This equation is in standard form a x 2 b x c = 0
Y=x^2+4x-5 vertex-Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more 5 points capitan1562 Asked Y=x^24x5 find the vertex See answers (1) Ask for details ;
Y=x^2+4x-5 vertexのギャラリー
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