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最高のコレクション y=x^2-4x-5 vertex 182207-Y=x^2+4x-5 vertex

2x^ {2}4xy=0 2 x 2 − 4 x − y = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 2 for a, 4 for b, and y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} This equation is in standard form a x 2 b x c = 0

Y=x^2+4x-5 vertex-Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more 5 points capitan1562 Asked Y=x^24x5 find the vertex See answers (1) Ask for details ;

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Click here👆to get an answer to your question ️ The length of the normal chord to the parabola y^2 = 4x which subtends a right angle at the vertex is Solve Study Textbooks Join / Login QuestionGiven an equation in vertex form, such as y = 4(x 3) 2 4, we can convert this to the standard form simply by multiplying the binomial and simplifying y = 4(x 3) 2 4 y = 4(x 2 6x 9) 4 y = 4x 2 24x 36 4 y = 4x 2 24x 40 So, the equation, y = 4(x 3) 2 4 and the equation y = 4x 2 24x 40 are the same, except in

Incoming Term: y=x^2+4x-5 vertex, y=x^2+4x-5 vertex form, identify the vertex of y=x^2+4x+5,

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